you need to comapre the measured velocities... not the power output, then just divide one by the other to get the %
however, as power is proportional to the square of velocity, the adjustment is the square root of 0.2/7.8 so about 1.6% probably
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you need to comapre the measured velocities... not the power output, then just divide one by the other to get the %
however, as power is proportional to the square of velocity, the adjustment is the square root of 0.2/7.8 so about 1.6% probably
Always looking for any cheap, interesting, knackered "project" guns. Thanks, JB.
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